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Find Consecutive Integers Whose Sum is Divisible by N

This calculator will help you find X consecutive integers whose sum is divisible by N.

Sum of Consecutive Integers is Divisible By N Calculator

For example, find three consecutive integers whose sum of them is divisible by 6? Enter 3 in the first input box, enter 6 in the second input box.

Calculate Reset

How to Calculate

For example, the sum of 4 consecutive integers is divisible by 12, what are these 4 integers?

Obviously, it is more difficult to calculate such a problem by hand. Since the sum is divisible by 12, it means that it is a multiple of 12, that is, 12, 24, 36, 48, 60… and so on. Then, for each multiple, find out whether there are consecutive integers that satisfy the condition. The whole process is lengthy and complicated. Although, we have a calculator to calculate consecutive integers based on sum, the whole process is not what we want. First, calculate the multiple, and then use the tool to solve it. Why not develop a tool to calculate the answer directly?

Therefore, we can’t wait to develop this calculator that the sum of consecutive integers can be divisible by N, eliminating all intermediate processes and calculating consecutive integers that meet the conditions in one step.

How to Use the Calculator

The procedure to use the sum of consecutive integers divisible by N calculator is very simple, just enter two related numbers.

  • 1Enter the number of consecutive integers into the first input box.
  • 2Enter the divisible number into the second input box.
  • 3Click the Calculate button to get the answer.
  • 4Click the Reset button to start a new calculation.

Next, let’s look at some examples.

Solved Examples Using the Calculator

Example 1: The sum of 4 consecutive integers is divisible by 13.

  • Enter 4 into the first input box.
  • Enter 13 into the second input box.
  • Finally, press Calculate button.

As the picture shows, the sum of 4 consecutive integers is divisible by 13, these consecutive integers are 5, 6, 7 and 8.

Or add tolerance 13 to get more consecutive integers like 18, 19, 20, 21 or 31, 32, 33, 34 and so on.

(5 + 6 + 7 + 8) / 13 = 26 / 13 = 2

(18 + 19 + 20 + 21) / 13 = 78 / 13 = 6

(31 + 32 + 33 + 34) / 13 = 130 / 13 = 10

The sum of 4 consecutive integers is divisible by 12

Example 2: Find 5 consecutive integers whose sum is divisible by 101?

  • Enter 5 into the first input box.
  • Enter 101 into the second input box.
  • Finally, press Calculate button.

As the picture shows, these 5 consecutive integers are 99, 100, 101, 102 and 103.

Or add tolerance 101 to get more consecutive integers like 200, 201, 202, 203, 204 or 301, 302, 303, 304, 305 and so on.

(99 + 100 + 101 + 102 + 103) / 101 = 505 / 101 = 5

(200 + 201 + 202 + 203 + 204) / 101 = 1010 / 101 = 10

(301 + 302 + 303 + 304 + 305) / 101 = 1515 / 101 = 15

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