Repeated Subtraction Counter

Input a minuend and a subtractor to instantly find out how many times the subtraction can occur before the minuend reaches zero or less.

Calculate the Number of Subtractions

Result

How to Calculate the Number of Subtractions

Let the minuend be \( A \), and the subtractor be \( B \). To find how many complete times \( A \) can be reduced by \( B \), follow these steps:

  1. Set Up the Equation: When subtracting \( B \) repeatedly from \( A \), the condition is: \( A - n \times B \geq 0 \), where \( n \) is the number of complete subtractions.
  2. Determine \( n \): Use integer division to calculate how many full subtractions are possible: \( n = \left\lfloor \frac{A}{B} \right\rfloor \) Here, the integer part of the division result represents the total number of full subtractions. The remainder (if any) is the part of \( A \) that cannot be further reduced by \( B \).

Examples

Example 1: How many times can be subtract 10 from 100?

Solution:

\( n = \frac{100}{10} = 10\)

Result: You can subtract 10 times.

Example 2: How many times can be subtract 28 from 1320?

Solution:

\( n = \frac{1320}{28} = 47…4\)

Result: You can subtract 47 full times, with a remainder of 4.

Example 3: How many times can be subtract 8 from 2560?

Solution:

\( n = \frac{2560}{8} = 320\)

Result: You can subtract 320 times.