Input a dataset to quickly calculate its median, quartiles, mode, midrange, mean, and range.
Given a dataset \( D = \{d_1, d_2, d_3, \dots, d_n\} \), you can calculate its key statistical values using the following methods:
The median is the middle value of a dataset when arranged in ascending order. If the dataset size \( n \) is odd, the median is the middle value. If \( n \) is even, the median is the average of the two middle values.
Formula:
Quartiles divide the dataset into four equal parts:
The mode is the value(s) that appear most frequently in the dataset. A dataset may have no mode, one mode, or multiple modes.
The midrange is the average of the dataset's maximum and minimum values. The formula is: \( \text{Midrange} = \frac{\text{Maximum Value} + \text{Minimum Value}}{2} \)
The mean (or average) is the sum of all data values divided by the number of values. The formula is: \( \text{Mean} = \frac{\sum_{i=1}^{n} d_i}{n} \)
The range is the difference between the maximum and minimum values in the dataset. The formula is: \( \text{Range} = \text{Maximum Value} - \text{Minimum Value} \)
Solution:
1. Median:
Dataset size = 8 (even).
Median = \(\frac{7 + 9}{2} = 8\).
2. Quartiles:
\( Q1 \): Median of \(\{1, 3, 5, 7\}\) = \(4\).
\( Q3 \): Median of \(\{9, 11, 13, 15\}\) = \(12\).
3. Mode:
No repeated values, so no mode.
4. Midrange:
\( \text{Midrange} = \frac{15 + 1}{2} = 8 \)
5. Mean:
\( \text{Mean} = \frac{1 + 3 + 5 + 7 + 9 + 11 + 13 + 15}{8} = \frac{64}{8} = 8 \)
6. Range:
\( \text{Range} = 15 - 1 = 14 \)
Solution:
1. Median:
Dataset size = 7 (odd). Median = \(6\).
2. Quartiles:
\( Q1 \): Median of \(\{2, 4, 4\}\) = \(4\).
\( Q3 \): Median of \(\{8, 8, 10\}\) = \(8\).
3. Mode:
Both \(4\) and \(8\) appear twice. Modes = \(4, 8\).
4. Midrange:
\( \text{Midrange} = \frac{10 + 2}{2} = 6 \)
5. Mean:
\( \text{Mean} = \frac{2 + 4 + 4 + 6 + 8 + 8 + 10}{7} = \frac{42}{7} = 6 \)
6. Range:
\( \text{Range} = 10 - 2 = 8 \)